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April 12, 2022
Here's a free roulette system for you.
It's based on the principles of two good systems: Repeating Numbers Version 2.0 and Awakening Numbers.
We know that within 38 spins all 38 numbers cannot be all different, thus some numbers will have to repeat.
Also not all numbers can sleep. They will eventually have to wake up.
They are both winning principles. Now we will combine the two.
Let's say, you come to the casino with a friend with the goal of sharing your profits at the end of your sessions.
You track 28 different numbers on the roulette table. Once ready, one of you bets on those 28 numbers with the hope that one of them will repeat. Your partner bets on the remaining 10 numbers (we're talking 00 wheel with 36 actual numbers and two zeros), with the hope that one of them will wake up.
One of the partners has to win, because they are both together covering all 38 numbers of the roulette wheel.
The player who bets on the repeating numbers has a
winning chance of 28/38 or 73.68%.
So, most likely, and not always necessarily, the repeating numbers player will win first. We will cover also the possibility of the sleeping numbers player to win first.
If the repeating numbers person wins first, he/she/(them) collects 36-28 = 8 chips and leaves the table with a profit of 8 units. If the unit size was, say, $10, that player wins $80 right away in one spin.
The sleeping numbers player has just lost 10 chips, remains at the table and continues to bet on the 10 sleeping numbers and places 10 chips on them again. If it's a win, the player has so far invested 20 chips and thus wins 36-20 = 16 chips and the session is over.
Combining their profits together, one wins 8 chips, the other 16, 24 chips overall. Sharing those profits, each wins 12 units in 3 spins.
Let's say now that the sleeping numbers player wins first. Having placed 10 chips on the table, this amounts to a winning of 36-10 = 26 chips and your partner leaves the table.
The repeating numbers player has just lost 28 chips. And because the sleeping number player has won, now there are 29 numbers to repeat. If the player continues to place 1 unit on those 29 numbers, and if the bet wins it won't be profitable, since the investment so far is 28 + 29 = 57 chips and the payout is 36. Thus one needs to bet 5 chips on those 29 numbers and the investment will be 5 X 29 + 28 = 173 chips. When one of the 29 numbers hits, the player cashes 5 X 36 = 180 chips profiting 180-173 = 7 units.
Combining both players profits, it amounts to 26 + 7 = 33 chips to share, where each profits 16.5 units again within 3 spins.
Now, if one finds the investment of the repeating numbers player too much, the unit size can be reduced from $10 to a lower value, such as $1 or $5 chips. The sleeping numbers player can stay at $10 bet size.
If the sleeping numbers player wins at the third bet, then the profit will be 36 - 20 = 16 units or $160, where the repeating numbers player wins at the first trial 36 - 28 = 8 units or $40 with a $5 bet on each number.
Sharing those profits again amounts to $160 + $40 = $200 or $100 each.
If you don't have a partner, you can do the following. Track 28 numbers on your own and don't bet yet. Simply observe if the winning side was on the repeating numbers' or the sleeping numbers' side, because covering 38 numbers on your own will make you lose 2 units up front.
Then depending on the side that wins, you continue your progression on the side that just lost until you end the session with a profit.
Moreover, since the roulette table has no memory, you can simply divide the table into two sections: numbers covering 1 to 28 and numbers covering 29-38 (including the two zeros). Then treat the 1-28 section as the numbers to repeat and the section of 0,00,28-36 as the numbers to wake up.
The outcome will be the same and you will quit with your profits and you don't need to share them.
I hope you liked this free system.
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